Two cars A as well as B proposed concurrently to cover a stretch of thirty km. Car A stoped in in in between for correct as well as finished rest of a tour during half a strange speed, due to that A reached 2 hours late than B reached a last destination. If relapse had occurred 10 km over than time 1 as well as a half hour relapse in in between A as well as B would have been. Find their speeds as well as relapse point. Given a speeds of a automobile have been in a comparative measure 3:4.
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let their speeds be 3x as well as 4x, as well as stretch in between relapse indicate as well as begin indicate is y.
then a initial time A outlay time: y/(3x)+(30-y)/(1.5x) as well as B outlay time: 30/(4x)
the second time A: (y+10)/(3x)+(20-y)/(1.5x) as well as B still: 30/(4x)
thus
y/(3x)+(30-y)/(1.5x)-30/(4x)=2
(y+10)/(3x)+(20-y)/(1.5x)-30/(4x)=0.5
and we goal we can do it yourself then, OK?